Two limits on a delivery load
A load can run out of space or reach its payload capacity first. Counting only truck-bed volume can understate the trips needed for a dense material. This calculator computes each limit separately and uses the larger trip count.
Measure and calculate
- Enter the order volume and density for the delivered material state.
- Use the carrier’s confirmed volume capacity and payload for this particular delivery.
- Inspect the volume-only and payload-only modes to see which constraint controls the combined result.
Trips = greater of ceiling(volume ÷ bed capacity) and ceiling(volume × density ÷ payload).
A worked example
- Inputs
- The order is 135 ft³ at 100 lb/ft³. The truck holds 135 ft³ but its stated payload is 12,000 lb.
- Calculation
Volume requires 1 trip. Weight is 13,500 lb, so payload requires ceiling(13,500 ÷ 12,000) = 2 trips.- Result
- 2 load
The combined estimate is 2 trips. This assumes the order can be split between loads; it does not establish a vehicle’s legal or safe capacity.
Read the result
| Output or check | What it means for your project |
|---|---|
| Combined trips | Use the larger of the volume-limited and payload-limited whole-trip counts. Both limits must be satisfied. |
| Which constraint controls? | Compare the separate modes. If weight requires two trips but space requires one, the combined result is two, assuming the material can be split between loads. |
| Carrier capacity | Use the carrier’s confirmed payload and usable volume for the delivery. The estimate does not certify a vehicle or loading arrangement. |
Common questions
Why can one truck-bed volume need two trips?
Filling the bed with a dense material may exceed the payload. The lower usable capacity controls each load.
Can I use compacted density for loose material?
Only if the volume is converted to the same material state first. Mixing loose volume with compacted density produces an inconsistent weight estimate.
